Base | Representation |
---|---|
bin | 10010101100101011… |
… | …01001010011001001 |
3 | 221220121010001201111 |
4 | 21112111221103021 |
5 | 131024320334403 |
6 | 4340034450321 |
7 | 503522261122 |
oct | 112625512311 |
9 | 27817101644 |
10 | 10038449353 |
11 | 4291496639 |
12 | 1b41a339a1 |
13 | c3c96027a |
14 | 6b32d1049 |
15 | 3db45556d |
hex | 2565694c9 |
10038449353 has 2 divisors, whose sum is σ = 10038449354. Its totient is φ = 10038449352.
The previous prime is 10038449273. The next prime is 10038449411. The reversal of 10038449353 is 35394483001.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9520295184 + 518154169 = 97572^2 + 22763^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10038449353 is a prime.
It is a super-2 number, since 2×100384493532 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10038449453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5019224676 + 5019224677.
It is an arithmetic number, because the mean of its divisors is an integer number (5019224677).
Almost surely, 210038449353 is an apocalyptic number.
It is an amenable number.
10038449353 is a deficient number, since it is larger than the sum of its proper divisors (1).
10038449353 is an equidigital number, since it uses as much as digits as its factorization.
10038449353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 40.
The spelling of 10038449353 in words is "ten billion, thirty-eight million, four hundred forty-nine thousand, three hundred fifty-three".
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