100401112013 has 2 divisors, whose sum is σ = 100401112014. Its totient is φ = 100401112012.

The previous prime is 100401112003. The next prime is 100401112079. The reversal of 100401112013 is 310211104001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82246783369 + 18154328644 = 286787^2 + 134738^2 .

It is an emirp because it is prime and its reverse (310211104001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100401112013 - 2¹⁶ = 100401046477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100401112003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50200556006 + 50200556007.

It is an arithmetic number, because the mean of its divisors is an integer number (50200556007).

Almost surely, 2^100401112013 is an apocalyptic number.

It is an amenable number.

100401112013 is a deficient number, since it is larger than the sum of its proper divisors (1).

100401112013 is an equidigital number, since it uses as much as digits as its factorization.

100401112013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 100401112013 its reverse (310211104001), we get a palindrome (410612216014).

The spelling of 100401112013 in words is "one hundred billion, four hundred one million, one hundred twelve thousand, thirteen".