100401114131 has 2 divisors, whose sum is σ = 100401114132. Its totient is φ = 100401114130.

The previous prime is 100401114119. The next prime is 100401114157. The reversal of 100401114131 is 131411104001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100401114131 - 2¹⁴ = 100401097747 is a prime.

It is a super-2 number, since 2×100401114131² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (100401114431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50200557065 + 50200557066.

It is an arithmetic number, because the mean of its divisors is an integer number (50200557066).

Almost surely, 2^100401114131 is an apocalyptic number.

100401114131 is a deficient number, since it is larger than the sum of its proper divisors (1).

100401114131 is an equidigital number, since it uses as much as digits as its factorization.

100401114131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 100401114131 its reverse (131411104001), we get a palindrome (231812218132).

The spelling of 100401114131 in words is "one hundred billion, four hundred one million, one hundred fourteen thousand, one hundred thirty-one".