1004013011 has 2 divisors, whose sum is σ = 1004013012. Its totient is φ = 1004013010.

The previous prime is 1004012983. The next prime is 1004013041. The reversal of 1004013011 is 1103104001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1004013011 - 2¹⁴ = 1003996627 is a prime.

It is a super-2 number, since 2×1004013011² = 2016084252514572242, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1004012983 and 1004013001.

It is not a weakly prime, because it can be changed into another prime (1004013041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502006505 + 502006506.

It is an arithmetic number, because the mean of its divisors is an integer number (502006506).

Almost surely, 2^1004013011 is an apocalyptic number.

1004013011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1004013011 is an equidigital number, since it uses as much as digits as its factorization.

1004013011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 1004013011 is about 31686.1643466040. The cubic root of 1004013011 is about 1001.3358849501.

Adding to 1004013011 its reverse (1103104001), we get a palindrome (2107117012).

The spelling of 1004013011 in words is "one billion, four million, thirteen thousand, eleven".