10040131313 has 4 divisors (see below), whose sum is σ = 10070464368. Its totient is φ = 10009798260.

The previous prime is 10040131253. The next prime is 10040131319. The reversal of 10040131313 is 31313104001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31313104001 = 8779 ⋅3566819.

It is a cyclic number.

It is not a de Polignac number, because 10040131313 - 2⁶ = 10040131249 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10040131291 and 10040131300.

It is not an unprimeable number, because it can be changed into a prime (10040131319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15166031 + ... + 15166692.

It is an arithmetic number, because the mean of its divisors is an integer number (2517616092).

Almost surely, 2^10040131313 is an apocalyptic number.

It is an amenable number.

10040131313 is a deficient number, since it is larger than the sum of its proper divisors (30333055).

10040131313 is an equidigital number, since it uses as much as digits as its factorization.

10040131313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30333054.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 10040131313 its reverse (31313104001), we get a palindrome (41353235314).

The spelling of 10040131313 in words is "ten billion, forty million, one hundred thirty-one thousand, three hundred thirteen".