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100401324113 is a prime number
BaseRepresentation
bin101110110000001100…
…0101010000001010001
3100121011010210201102202
41131200120222001101
53121110214332423
6114042420452545
710153016113436
oct1354030520121
9317133721382
10100401324113
1139641a25922
121756024a155
1396109c592c
144c0648bb8d
1529295b0728
hex176062a051

100401324113 has 2 divisors, whose sum is σ = 100401324114. Its totient is φ = 100401324112.

The previous prime is 100401324091. The next prime is 100401324143. The reversal of 100401324113 is 311423104001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 58405838929 + 41995485184 = 241673^2 + 204928^2 .

It is a cyclic number.

It is not a de Polignac number, because 100401324113 - 210 = 100401323089 is a prime.

It is not a weakly prime, because it can be changed into another prime (100401324143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50200662056 + 50200662057.

It is an arithmetic number, because the mean of its divisors is an integer number (50200662057).

Almost surely, 2100401324113 is an apocalyptic number.

It is an amenable number.

100401324113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100401324113 is an equidigital number, since it uses as much as digits as its factorization.

100401324113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 100401324113 its reverse (311423104001), we get a palindrome (411824428114).

The spelling of 100401324113 in words is "one hundred billion, four hundred one million, three hundred twenty-four thousand, one hundred thirteen".