1004031113531 has 4 divisors (see below), whose sum is σ = 1008454158312. Its totient is φ = 999608068752.

The previous prime is 1004031113521. The next prime is 1004031113581. The reversal of 1004031113531 is 1353111304001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1004031113531 - 2¹⁰ = 1004031112507 is a prime.

It is a super-2 number, since 2×1004031113531² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1004031113497 and 1004031113506.

It is not an unprimeable number, because it can be changed into a prime (1004031113521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2211522050 + ... + 2211522503.

It is an arithmetic number, because the mean of its divisors is an integer number (252113539578).

Almost surely, 2^{1004031113531} is an apocalyptic number.

1004031113531 is a deficient number, since it is larger than the sum of its proper divisors (4423044781).

1004031113531 is an equidigital number, since it uses as much as digits as its factorization.

1004031113531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4423044780.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 1004031113531 its reverse (1353111304001), we get a palindrome (2357142417532).

The spelling of 1004031113531 in words is "one trillion, four billion, thirty-one million, one hundred thirteen thousand, five hundred thirty-one".