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1004031132463 = 1217825005039
BaseRepresentation
bin11101001110001001110…
…10110100001100101111
310112222120122201011122101
432213010322310030233
5112422223432214323
62045125011355531
7132352553545552
oct16470472641457
93488518634571
101004031132463
11357897443427
12142707bb2ba7
13738ab49a818
1436849982699
151b1b55dadad
hexe9c4eb432f

1004031132463 has 4 divisors (see below), whose sum is σ = 1004856138720. Its totient is φ = 1003206126208.

The previous prime is 1004031132413. The next prime is 1004031132527. The reversal of 1004031132463 is 3642311304001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1004031132463 - 233 = 995441197871 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1004031132413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 412501303 + ... + 412503736.

It is an arithmetic number, because the mean of its divisors is an integer number (251214034680).

Almost surely, 21004031132463 is an apocalyptic number.

1004031132463 is a deficient number, since it is larger than the sum of its proper divisors (825006257).

1004031132463 is an equidigital number, since it uses as much as digits as its factorization.

1004031132463 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 825006256.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1004031132463 its reverse (3642311304001), we get a palindrome (4646342436464).

The spelling of 1004031132463 in words is "one trillion, four billion, thirty-one million, one hundred thirty-two thousand, four hundred sixty-three".

Divisors: 1 1217 825005039 1004031132463