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100404101131 = 617920835049
BaseRepresentation
bin101110110000010001…
…1010000000000001011
3100121011100000210210021
41131200203100000023
53121111422214011
6114043000201311
710153051530625
oct1354043200013
9317140023707
10100404101131
1139643552284
1217561169237
139611458939
144c069b1c15
15292995d471
hex17608d000b

100404101131 has 8 divisors (see below), whose sum is σ = 103341848000. Its totient is φ = 97508024640.

The previous prime is 100404101129. The next prime is 100404101167. The reversal of 100404101131 is 131101404001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100404101131 - 21 = 100404101129 is a prime.

It is a super-2 number, since 2×1004041011312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100404101191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10412706 + ... + 10422343.

It is an arithmetic number, because the mean of its divisors is an integer number (12917731000).

Almost surely, 2100404101131 is an apocalyptic number.

100404101131 is a deficient number, since it is larger than the sum of its proper divisors (2937746869).

100404101131 is an equidigital number, since it uses as much as digits as its factorization.

100404101131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20835189.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 100404101131 its reverse (131101404001), we get a palindrome (231505505132).

The spelling of 100404101131 in words is "one hundred billion, four hundred four million, one hundred one thousand, one hundred thirty-one".

Divisors: 1 61 79 4819 20835049 1270937989 1645968871 100404101131