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10040434104115 = 53754272616779
BaseRepresentation
bin1001001000011011100010…
…0000100001011100110011
31022112212010010010120020001
42102012320200201130303
52304000302112312430
633204302312130431
72054253213510622
oct222067040413463
938485103116201
1010040434104115
113221140330998
121161aa1096a17
1357aa6913040c
14269d6121b6b9
15126294ac83ca
hex921b8821733

10040434104115 has 8 divisors (see below), whose sum is σ = 12374156625840. Its totient is φ = 7815256816032.

The previous prime is 10040434104097. The next prime is 10040434104133. The reversal of 10040434104115 is 51140143404001.

It is an interprime number because it is at equal distance from previous prime (10040434104097) and next prime (10040434104133).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10040434104115 - 215 = 10040434071347 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27136308205 + ... + 27136308574.

It is an arithmetic number, because the mean of its divisors is an integer number (1546769578230).

Almost surely, 210040434104115 is an apocalyptic number.

10040434104115 is a deficient number, since it is larger than the sum of its proper divisors (2333722521725).

10040434104115 is an equidigital number, since it uses as much as digits as its factorization.

10040434104115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54272616821.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 10040434104115 its reverse (51140143404001), we get a palindrome (61180577508116).

The spelling of 10040434104115 in words is "ten trillion, forty billion, four hundred thirty-four million, one hundred four thousand, one hundred fifteen".

Divisors: 1 5 37 185 54272616779 271363083895 2008086820823 10040434104115