100404859116257 has 4 divisors (see below), whose sum is σ = 100442365603476. Its totient is φ = 100367352629040.

The previous prime is 100404859116209. The next prime is 100404859116271. The reversal of 100404859116257 is 752611958404001.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 41832837844561 + 58572021271696 = 6467831^2 + 7653236^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100404859116257 is a prime.

It is a super-3 number, since 3×100404859116257³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100404859116199 and 100404859116208.

It is not an unprimeable number, because it can be changed into a prime (100404819116257) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18753239594 + ... + 18753244947.

It is an arithmetic number, because the mean of its divisors is an integer number (25110591400869).

Almost surely, 2^{100404859116257} is an apocalyptic number.

It is an amenable number.

100404859116257 is a deficient number, since it is larger than the sum of its proper divisors (37506487219).

100404859116257 is an equidigital number, since it uses as much as digits as its factorization.

100404859116257 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37506487218.

The product of its (nonzero) digits is 2419200, while the sum is 53.

The spelling of 100404859116257 in words is "one hundred trillion, four hundred four billion, eight hundred fifty-nine million, one hundred sixteen thousand, two hundred fifty-seven".