Base | Representation |
---|---|
bin | 11101001110001100100… |
… | …10111010000011100111 |
3 | 10112222122021011101211020 |
4 | 32213012102322003213 |
5 | 112422300340201002 |
6 | 2045131154342223 |
7 | 132353254045242 |
oct | 16470622720347 |
9 | 3488567141736 |
10 | 1004054225127 |
11 | 3578a9486278 |
12 | 14271388a973 |
13 | 738b31c4815 |
14 | 3684ca74259 |
15 | 1b1b764d2bc |
hex | e9c64ba0e7 |
1004054225127 has 8 divisors (see below), whose sum is σ = 1339575162480. Its totient is φ = 668951385600.
The previous prime is 1004054225023. The next prime is 1004054225183. The reversal of 1004054225127 is 7215224504001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1004054225127 - 215 = 1004054192359 is a prime.
It is a super-2 number, since 2×10040542251272 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1004054229127) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 104518852 + ... + 104528457.
It is an arithmetic number, because the mean of its divisors is an integer number (167446895310).
Almost surely, 21004054225127 is an apocalyptic number.
1004054225127 is a deficient number, since it is larger than the sum of its proper divisors (335520937353).
1004054225127 is a wasteful number, since it uses less digits than its factorization.
1004054225127 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 209048913.
The product of its (nonzero) digits is 22400, while the sum is 33.
Adding to 1004054225127 its reverse (7215224504001), we get a palindrome (8219278729128).
The spelling of 1004054225127 in words is "one trillion, four billion, fifty-four million, two hundred twenty-five thousand, one hundred twenty-seven".
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