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10041104212313 is a prime number
BaseRepresentation
bin1001001000011110000001…
…1100110010000101011001
31022112220211211001120212012
42102013200130302011121
52304003140134243223
633204453010555305
72054305631364056
oct222074034620531
938486754046765
1010041104212313
113221454614119
121162049598b35
1357ab44c04b45
14269dc621402d
151262d3843c78
hex921e0732159

10041104212313 has 2 divisors, whose sum is σ = 10041104212314. Its totient is φ = 10041104212312.

The previous prime is 10041104212309. The next prime is 10041104212333. The reversal of 10041104212313 is 31321240114001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5952955857424 + 4088148354889 = 2439868^2 + 2021917^2 .

It is a cyclic number.

It is not a de Polignac number, because 10041104212313 - 22 = 10041104212309 is a prime.

It is a super-3 number, since 3×100411042123133 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (10041104212333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020552106156 + 5020552106157.

It is an arithmetic number, because the mean of its divisors is an integer number (5020552106157).

Almost surely, 210041104212313 is an apocalyptic number.

It is an amenable number.

10041104212313 is a deficient number, since it is larger than the sum of its proper divisors (1).

10041104212313 is an equidigital number, since it uses as much as digits as its factorization.

10041104212313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 10041104212313 its reverse (31321240114001), we get a palindrome (41362344326314).

The spelling of 10041104212313 in words is "ten trillion, forty-one billion, one hundred four million, two hundred twelve thousand, three hundred thirteen".