10041143311 has 2 divisors, whose sum is σ = 10041143312. Its totient is φ = 10041143310.

The previous prime is 10041143297. The next prime is 10041143353. The reversal of 10041143311 is 11334114001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10041143311 - 2¹⁵ = 10041110543 is a prime.

It is a super-3 number, since 3×10041143311³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10041143011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020571655 + 5020571656.

It is an arithmetic number, because the mean of its divisors is an integer number (5020571656).

Almost surely, 2^10041143311 is an apocalyptic number.

10041143311 is a deficient number, since it is larger than the sum of its proper divisors (1).

10041143311 is an equidigital number, since it uses as much as digits as its factorization.

10041143311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10041143311 its reverse (11334114001), we get a palindrome (21375257312).

The spelling of 10041143311 in words is "ten billion, forty-one million, one hundred forty-three thousand, three hundred eleven".