Base | Representation |
---|---|
bin | 101110110000100000… |
… | …1111000001100100011 |
3 | 100121011220010201102212 |
4 | 1131201001320030203 |
5 | 3121121001130313 |
6 | 114043444232335 |
7 | 10153210010636 |
oct | 1354101701443 |
9 | 317156121385 |
10 | 100412130083 |
11 | 39648036581 |
12 | 1756399b6ab |
13 | 961300a2b5 |
14 | 4c07aa1c1d |
15 | 292a4e73a8 |
hex | 1761078323 |
100412130083 has 2 divisors, whose sum is σ = 100412130084. Its totient is φ = 100412130082.
The previous prime is 100412129957. The next prime is 100412130089. The reversal of 100412130083 is 380031214001.
It is a strong prime.
It is an emirp because it is prime and its reverse (380031214001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100412130083 - 28 = 100412129827 is a prime.
It is not a weakly prime, because it can be changed into another prime (100412130089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50206065041 + 50206065042.
It is an arithmetic number, because the mean of its divisors is an integer number (50206065042).
Almost surely, 2100412130083 is an apocalyptic number.
100412130083 is a deficient number, since it is larger than the sum of its proper divisors (1).
100412130083 is an equidigital number, since it uses as much as digits as its factorization.
100412130083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 100412130083 its reverse (380031214001), we get a palindrome (480443344084).
The spelling of 100412130083 in words is "one hundred billion, four hundred twelve million, one hundred thirty thousand, eighty-three".
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