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10041214333 is a prime number
BaseRepresentation
bin10010101101000000…
…01100010101111101
3221220210022112120011
421112200030111331
5131031022324313
64340214023221
7503554625233
oct112640142575
927823275504
1010041214333
114293004a47
121b42947b11
13c403ba957
146b3810953
153db7ee93d
hex25680c57d

10041214333 has 2 divisors, whose sum is σ = 10041214334. Its totient is φ = 10041214332.

The previous prime is 10041214289. The next prime is 10041214363. The reversal of 10041214333 is 33341214001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9800406009 + 240808324 = 98997^2 + 15518^2 .

It is an emirp because it is prime and its reverse (33341214001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10041214333 - 225 = 10007659901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10041214363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020607166 + 5020607167.

It is an arithmetic number, because the mean of its divisors is an integer number (5020607167).

Almost surely, 210041214333 is an apocalyptic number.

It is an amenable number.

10041214333 is a deficient number, since it is larger than the sum of its proper divisors (1).

10041214333 is an equidigital number, since it uses as much as digits as its factorization.

10041214333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 10041214333 its reverse (33341214001), we get a palindrome (43382428334).

The spelling of 10041214333 in words is "ten billion, forty-one million, two hundred fourteen thousand, three hundred thirty-three".