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10041232433 = 26338179591
BaseRepresentation
bin10010101101000000…
…10000110000110001
3221220210100110101112
421112200100300301
5131031023414213
64340214243105
7503555032061
oct112640206061
927823313345
1010041232433
114293017601
121b42956495
13c403c5c6b
146b38173a1
153db804ea8
hex256810c31

10041232433 has 4 divisors (see below), whose sum is σ = 10079412288. Its totient is φ = 10003052580.

The previous prime is 10041232403. The next prime is 10041232441. The reversal of 10041232433 is 33423214001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10041232433 - 28 = 10041232177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10041232399 and 10041232408.

It is not an unprimeable number, because it can be changed into a prime (10041232403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19089533 + ... + 19090058.

It is an arithmetic number, because the mean of its divisors is an integer number (2519853072).

Almost surely, 210041232433 is an apocalyptic number.

It is an amenable number.

10041232433 is a deficient number, since it is larger than the sum of its proper divisors (38179855).

10041232433 is an equidigital number, since it uses as much as digits as its factorization.

10041232433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38179854.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 10041232433 its reverse (33423214001), we get a palindrome (43464446434).

The spelling of 10041232433 in words is "ten billion, forty-one million, two hundred thirty-two thousand, four hundred thirty-three".

Divisors: 1 263 38179591 10041232433