100413331321551 has 4 divisors (see below), whose sum is σ = 133884441762072. Its totient is φ = 66942220881032.

The previous prime is 100413331321543. The next prime is 100413331321553. The reversal of 100413331321551 is 155123133314001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100413331321551 - 2³ = 100413331321543 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100413331321553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16735555220256 + ... + 16735555220261.

It is an arithmetic number, because the mean of its divisors is an integer number (33471110440518).

Almost surely, 2^{100413331321551} is an apocalyptic number.

100413331321551 is a deficient number, since it is larger than the sum of its proper divisors (33471110440521).

100413331321551 is an equidigital number, since it uses as much as digits as its factorization.

100413331321551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33471110440520.

The product of its (nonzero) digits is 16200, while the sum is 33.

Adding to 100413331321551 its reverse (155123133314001), we get a palindrome (255536464635552).

The spelling of 100413331321551 in words is "one hundred trillion, four hundred thirteen billion, three hundred thirty-one million, three hundred twenty-one thousand, five hundred fifty-one".