Base | Representation |
---|---|
bin | 1001001000011111100001… |
… | …0111010001111111100011 |
3 | 1022112221212210000012220112 |
4 | 2102013320113101333203 |
5 | 2304010000342021311 |
6 | 33205000502201535 |
7 | 2054321602541354 |
oct | 222077027217743 |
9 | 38487783005815 |
10 | 10041505423331 |
11 | 3221640036978 |
12 | 116213ba232ab |
13 | 57abaa07b705 |
14 | 26a023611d2b |
15 | 126308b9628b |
hex | 921f85d1fe3 |
10041505423331 has 2 divisors, whose sum is σ = 10041505423332. Its totient is φ = 10041505423330.
The previous prime is 10041505423289. The next prime is 10041505423333. The reversal of 10041505423331 is 13332450514001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10041505423331 - 210 = 10041505422307 is a prime.
It is a super-2 number, since 2×100415054233312 (a number of 27 digits) contains 22 as substring.
Together with 10041505423333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10041505423333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020752711665 + 5020752711666.
It is an arithmetic number, because the mean of its divisors is an integer number (5020752711666).
Almost surely, 210041505423331 is an apocalyptic number.
10041505423331 is a deficient number, since it is larger than the sum of its proper divisors (1).
10041505423331 is an equidigital number, since it uses as much as digits as its factorization.
10041505423331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 10041505423331 its reverse (13332450514001), we get a palindrome (23373955937332).
The spelling of 10041505423331 in words is "ten trillion, forty-one billion, five hundred five million, four hundred twenty-three thousand, three hundred thirty-one".
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