10042012113 has 8 divisors (see below), whose sum is σ = 15302113728. Its totient is φ = 5738292624.

The previous prime is 10042012109. The next prime is 10042012117. The reversal of 10042012113 is 31121024001.

10042012113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (10042012109) and next prime (10042012117).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10042012113 - 2² = 10042012109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10042012092 and 10042012101.

It is not an unprimeable number, because it can be changed into a prime (10042012117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 239095506 + ... + 239095547.

It is an arithmetic number, because the mean of its divisors is an integer number (1912764216).

Almost surely, 2^10042012113 is an apocalyptic number.

It is an amenable number.

10042012113 is a deficient number, since it is larger than the sum of its proper divisors (5260101615).

10042012113 is an equidigital number, since it uses as much as digits as its factorization.

10042012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 478191063.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 10042012113 its reverse (31121024001), we get a palindrome (41163036114).

The spelling of 10042012113 in words is "ten billion, forty-two million, twelve thousand, one hundred thirteen".