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1004215455013 = 4323353847791
BaseRepresentation
bin11101001110011111110…
…01111100110100100101
310120000001111112201122111
432213033321330310211
5112423113124030023
62045155154201021
7132360252346231
oct16471771746445
93500044481574
101004215455013
11357981498711
12142759883171
137390a726014
14368662435c1
151b1c689a00d
hexe9cfe7cd25

1004215455013 has 4 divisors (see below), whose sum is σ = 1027569302848. Its totient is φ = 980861607180.

The previous prime is 1004215454993. The next prime is 1004215455017. The reversal of 1004215455013 is 3105545124001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1004215455013 - 229 = 1003678584101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1004215455017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11676923853 + ... + 11676923938.

It is an arithmetic number, because the mean of its divisors is an integer number (256892325712).

Almost surely, 21004215455013 is an apocalyptic number.

It is an amenable number.

1004215455013 is a deficient number, since it is larger than the sum of its proper divisors (23353847835).

1004215455013 is an equidigital number, since it uses as much as digits as its factorization.

1004215455013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23353847834.

The product of its (nonzero) digits is 12000, while the sum is 31.

The spelling of 1004215455013 in words is "one trillion, four billion, two hundred fifteen million, four hundred fifty-five thousand, thirteen".

Divisors: 1 43 23353847791 1004215455013