100423433113 has 4 divisors (see below), whose sum is σ = 100480526080. Its totient is φ = 100366340148.

The previous prime is 100423433101. The next prime is 100423433119. The reversal of 100423433113 is 311334324001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311334324001 = 4451 ⋅69947051.

It is a cyclic number.

It is not a de Polignac number, because 100423433113 - 2¹⁷ = 100423302041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100423433119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28543845 + ... + 28547362.

It is an arithmetic number, because the mean of its divisors is an integer number (25120131520).

Almost surely, 2^100423433113 is an apocalyptic number.

It is an amenable number.

100423433113 is a deficient number, since it is larger than the sum of its proper divisors (57092967).

100423433113 is an equidigital number, since it uses as much as digits as its factorization.

100423433113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57092966.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 100423433113 its reverse (311334324001), we get a palindrome (411757757114).

The spelling of 100423433113 in words is "one hundred billion, four hundred twenty-three million, four hundred thirty-three thousand, one hundred thirteen".