1004240113131 has 8 divisors (see below), whose sum is σ = 1339026625024. Its totient is φ = 669473505000.

The previous prime is 1004240113109. The next prime is 1004240113169. The reversal of 1004240113131 is 1313110424001.

1004240113131 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1004240113131 - 2¹³ = 1004240104939 is a prime.

It is a super-2 number, since 2×1004240113131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1004240113098 and 1004240113107.

It is not an unprimeable number, because it can be changed into a prime (1004240113531) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4857811 + ... + 5060316.

It is an arithmetic number, because the mean of its divisors is an integer number (167378328128).

Almost surely, 2^{1004240113131} is an apocalyptic number.

1004240113131 is a deficient number, since it is larger than the sum of its proper divisors (334786511893).

1004240113131 is an equidigital number, since it uses as much as digits as its factorization.

1004240113131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9951881.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 1004240113131 its reverse (1313110424001), we get a palindrome (2317350537132).

The spelling of 1004240113131 in words is "one trillion, four billion, two hundred forty million, one hundred thirteen thousand, one hundred thirty-one".