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1004302224113 = 5020632000351
BaseRepresentation
bin11101001110101010001…
…00111100101011110001
310120000021112211001110212
432213111010330223301
5112423302332132423
62045211534033505
7132362355024326
oct16472504745361
93500245731425
101004302224113
11357a16472611
12142782948895
13739226b6496
143687398cb4d
151b1ce2d9578
hexe9d513caf1

1004302224113 has 4 divisors (see below), whose sum is σ = 1004304726528. Its totient is φ = 1004299721700.

The previous prime is 1004302224083. The next prime is 1004302224203. The reversal of 1004302224113 is 3114222034001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1004302224113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1004302224313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 498113 + ... + 1502238.

It is an arithmetic number, because the mean of its divisors is an integer number (251076181632).

Almost surely, 21004302224113 is an apocalyptic number.

It is an amenable number.

1004302224113 is a deficient number, since it is larger than the sum of its proper divisors (2502415).

1004302224113 is an equidigital number, since it uses as much as digits as its factorization.

1004302224113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2502414.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1004302224113 its reverse (3114222034001), we get a palindrome (4118524258114).

The spelling of 1004302224113 in words is "one trillion, four billion, three hundred two million, two hundred twenty-four thousand, one hundred thirteen".

Divisors: 1 502063 2000351 1004302224113