Base | Representation |
---|---|
bin | 10010101101001110… |
… | …01010000100000001 |
3 | 221220220202021220111 |
4 | 21112213022010001 |
5 | 131032004240001 |
6 | 4340321111321 |
7 | 503606301001 |
oct | 112647120401 |
9 | 27826667814 |
10 | 10043040001 |
11 | 4294041665 |
12 | 1b43488541 |
13 | c408a9927 |
14 | 6b3b68001 |
15 | 3dba60851 |
hex | 2569ca101 |
10043040001 has 2 divisors, whose sum is σ = 10043040002. Its totient is φ = 10043040000.
The previous prime is 10043039989. The next prime is 10043040011. The reversal of 10043040001 is 10004034001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6072149776 + 3970890225 = 77924^2 + 63015^2 .
It is a cyclic number.
It is not a de Polignac number, because 10043040001 - 217 = 10042908929 is a prime.
It is not a weakly prime, because it can be changed into another prime (10043040011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021520000 + 5021520001.
It is an arithmetic number, because the mean of its divisors is an integer number (5021520001).
Almost surely, 210043040001 is an apocalyptic number.
It is an amenable number.
10043040001 is a deficient number, since it is larger than the sum of its proper divisors (1).
10043040001 is an equidigital number, since it uses as much as digits as its factorization.
10043040001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 10043040001 its reverse (10004034001), we get a palindrome (20047074002).
The spelling of 10043040001 in words is "ten billion, forty-three million, forty thousand, one".
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