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100431331141 = 127790797883
BaseRepresentation
bin101110110001000101…
…1000111111101000101
3100121020020021020100011
41131202023013331011
53121140410044031
6114045411550221
710153532141461
oct1354213077505
9317206236304
10100431331141
1139657960619
121756a2bb371
139616ca0b7b
144c0a45d4a1
15292c03b6b1
hex17622c7f45

100431331141 has 4 divisors (see below), whose sum is σ = 101222129152. Its totient is φ = 99640533132.

The previous prime is 100431331139. The next prime is 100431331153. The reversal of 100431331141 is 141133134001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100431331141 - 21 = 100431331139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100431331111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 395398815 + ... + 395399068.

It is an arithmetic number, because the mean of its divisors is an integer number (25305532288).

Almost surely, 2100431331141 is an apocalyptic number.

It is an amenable number.

100431331141 is a deficient number, since it is larger than the sum of its proper divisors (790798011).

100431331141 is an equidigital number, since it uses as much as digits as its factorization.

100431331141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 790798010.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 100431331141 its reverse (141133134001), we get a palindrome (241564465142).

The spelling of 100431331141 in words is "one hundred billion, four hundred thirty-one million, three hundred thirty-one thousand, one hundred forty-one".

Divisors: 1 127 790797883 100431331141