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10043212331 is a prime number
BaseRepresentation
bin10010101101001111…
…10100001000101011
3221220221002001022002
421112213310020223
5131032030243311
64340324521215
7503610616265
oct112647641053
927827061262
1010043212331
11429414a089
121b4355020b
13c4093a1b9
146b3bb0b35
153dba9693b
hex2569f422b

10043212331 has 2 divisors, whose sum is σ = 10043212332. Its totient is φ = 10043212330.

The previous prime is 10043212313. The next prime is 10043212363. The reversal of 10043212331 is 13321234001.

10043212331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (10043212313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10043212331 - 210 = 10043211307 is a prime.

It is a super-2 number, since 2×100432123312 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10043212301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021606165 + 5021606166.

It is an arithmetic number, because the mean of its divisors is an integer number (5021606166).

Almost surely, 210043212331 is an apocalyptic number.

10043212331 is a deficient number, since it is larger than the sum of its proper divisors (1).

10043212331 is an equidigital number, since it uses as much as digits as its factorization.

10043212331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 10043212331 its reverse (13321234001), we get a palindrome (23364446332).

The spelling of 10043212331 in words is "ten billion, forty-three million, two hundred twelve thousand, three hundred thirty-one".