100433041340969 has 2 divisors, whose sum is σ = 100433041340970. Its totient is φ = 100433041340968.

The previous prime is 100433041340963. The next prime is 100433041340971. The reversal of 100433041340969 is 969043140334001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91434961238569 + 8998080102400 = 9562163^2 + 2999680^2 .

It is an emirp because it is prime and its reverse (969043140334001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100433041340969 - 2⁴ = 100433041340953 is a prime.

It is a super-2 number, since 2×100433041340969² (a number of 29 digits) contains 22 as substring.

Together with 100433041340971, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (100433041340963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50216520670484 + 50216520670485.

It is an arithmetic number, because the mean of its divisors is an integer number (50216520670485).

Almost surely, 2^{100433041340969} is an apocalyptic number.

It is an amenable number.

100433041340969 is a deficient number, since it is larger than the sum of its proper divisors (1).

100433041340969 is an equidigital number, since it uses as much as digits as its factorization.

100433041340969 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 839808, while the sum is 47.

The spelling of 100433041340969 in words is "one hundred trillion, four hundred thirty-three billion, forty-one million, three hundred forty thousand, nine hundred sixty-nine".