Base | Representation |
---|---|
bin | 10010101101010000… |
… | …10001101101111001 |
3 | 221220221022012111201 |
4 | 21112220101231321 |
5 | 131032043132442 |
6 | 4340331254201 |
7 | 503611632451 |
oct | 112650215571 |
9 | 27827265451 |
10 | 10043333497 |
11 | 429422211a |
12 | 1b435aa361 |
13 | c409803b2 |
14 | 6b3c02d61 |
15 | 3dbabc7b7 |
hex | 256a11b79 |
10043333497 has 2 divisors, whose sum is σ = 10043333498. Its totient is φ = 10043333496.
The previous prime is 10043333429. The next prime is 10043333533. The reversal of 10043333497 is 79433334001.
10043333497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5803240041 + 4240093456 = 76179^2 + 65116^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10043333497 is a prime.
It is not a weakly prime, because it can be changed into another prime (10043333297) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021666748 + 5021666749.
It is an arithmetic number, because the mean of its divisors is an integer number (5021666749).
Almost surely, 210043333497 is an apocalyptic number.
It is an amenable number.
10043333497 is a deficient number, since it is larger than the sum of its proper divisors (1).
10043333497 is an equidigital number, since it uses as much as digits as its factorization.
10043333497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81648, while the sum is 37.
Adding to 10043333497 its reverse (79433334001), we get a palindrome (89476667498).
The spelling of 10043333497 in words is "ten billion, forty-three million, three hundred thirty-three thousand, four hundred ninety-seven".
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