Base | Representation |
---|---|
bin | 10010101101010001… |
… | …00100011111110111 |
3 | 221220221110010000211 |
4 | 21112220210133313 |
5 | 131032103113143 |
6 | 4340333050251 |
7 | 503612402644 |
oct | 112650443767 |
9 | 27827403024 |
10 | 10043410423 |
11 | 42942749a2 |
12 | 1b43626987 |
13 | c409a9407 |
14 | 6b3c22dcb |
15 | 3dbad549d |
hex | 256a247f7 |
10043410423 has 2 divisors, whose sum is σ = 10043410424. Its totient is φ = 10043410422.
The previous prime is 10043410397. The next prime is 10043410451. The reversal of 10043410423 is 32401434001.
10043410423 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10043410423 - 225 = 10009855991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10043410394 and 10043410403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10043410493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021705211 + 5021705212.
It is an arithmetic number, because the mean of its divisors is an integer number (5021705212).
Almost surely, 210043410423 is an apocalyptic number.
10043410423 is a deficient number, since it is larger than the sum of its proper divisors (1).
10043410423 is an equidigital number, since it uses as much as digits as its factorization.
10043410423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 10043410423 its reverse (32401434001), we get a palindrome (42444844424).
The spelling of 10043410423 in words is "ten billion, forty-three million, four hundred ten thousand, four hundred twenty-three".
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