100434121 has 4 divisors (see below), whose sum is σ = 102080644. Its totient is φ = 98787600.

The previous prime is 100434083. The next prime is 100434143. The reversal of 100434121 is 121434001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 121434001 = 13 ⋅9341077.

It can be written as a sum of positive squares in 2 ways, for example, as 44408896 + 56025225 = 6664^2 + 7485^2 .

It is a cyclic number.

It is not a de Polignac number, because 100434121 - 2¹³ = 100425929 is a prime.

It is a super-2 number, since 2×100434121² = 20174025322085282, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100434095 and 100434104.

It is not an unprimeable number, because it can be changed into a prime (100434821) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 823170 + ... + 823291.

It is an arithmetic number, because the mean of its divisors is an integer number (25520161).

Almost surely, 2^100434121 is an apocalyptic number.

It is an amenable number.

100434121 is a deficient number, since it is larger than the sum of its proper divisors (1646523).

100434121 is an equidigital number, since it uses as much as digits as its factorization.

100434121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1646522.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 100434121 is about 10021.6825433657. The cubic root of 100434121 is about 464.8295841399.

Adding to 100434121 its reverse (121434001), we get a palindrome (221868122).

The spelling of 100434121 in words is "one hundred million, four hundred thirty-four thousand, one hundred twenty-one".