Base | Representation |
---|---|
bin | 10110110101101000010010… |
… | …111101111010000000110111 |
3 | 111011122012110012000001010001 |
4 | 112311220102331322000313 |
5 | 101131122040342340201 |
6 | 553342340131412131 |
7 | 30104503613050516 |
oct | 2665502275720067 |
9 | 434565405001101 |
10 | 100442423402551 |
11 | 2a00543553383a |
12 | b3224b8454047 |
13 | 44078ab927539 |
14 | 1ab362137467d |
15 | b92b107ea301 |
hex | 5b5a12f7a037 |
100442423402551 has 2 divisors, whose sum is σ = 100442423402552. Its totient is φ = 100442423402550.
The previous prime is 100442423402443. The next prime is 100442423402603. The reversal of 100442423402551 is 155204324244001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100442423402551 - 223 = 100442415013943 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 100442423402551.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100442423402351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50221211701275 + 50221211701276.
It is an arithmetic number, because the mean of its divisors is an integer number (50221211701276).
Almost surely, 2100442423402551 is an apocalyptic number.
100442423402551 is a deficient number, since it is larger than the sum of its proper divisors (1).
100442423402551 is an equidigital number, since it uses as much as digits as its factorization.
100442423402551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 153600, while the sum is 37.
Adding to 100442423402551 its reverse (155204324244001), we get a palindrome (255646747646552).
The spelling of 100442423402551 in words is "one hundred trillion, four hundred forty-two billion, four hundred twenty-three million, four hundred two thousand, five hundred fifty-one".
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