Base | Representation |
---|---|
bin | 10110110101101100111110… |
… | …100110001101100110100011 |
3 | 111011122200102112002202000222 |
4 | 112311230332212031212203 |
5 | 101131212334242344011 |
6 | 553344531024433255 |
7 | 30105042313335044 |
oct | 2665547646154643 |
9 | 434580375082028 |
10 | 100447450356131 |
11 | 2a00758508042a |
12 | b32347ba7882b |
13 | 4408200232598 |
14 | 1ab397ac508cb |
15 | b92d06cc7ddb |
hex | 5b5b3e98d9a3 |
100447450356131 has 2 divisors, whose sum is σ = 100447450356132. Its totient is φ = 100447450356130.
The previous prime is 100447450356109. The next prime is 100447450356133. The reversal of 100447450356131 is 131653054744001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100447450356131 is a prime.
It is a super-2 number, since 2×1004474503561312 (a number of 29 digits) contains 22 as substring.
Together with 100447450356133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (100447450356133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50223725178065 + 50223725178066.
It is an arithmetic number, because the mean of its divisors is an integer number (50223725178066).
Almost surely, 2100447450356131 is an apocalyptic number.
100447450356131 is a deficient number, since it is larger than the sum of its proper divisors (1).
100447450356131 is an equidigital number, since it uses as much as digits as its factorization.
100447450356131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 604800, while the sum is 44.
The spelling of 100447450356131 in words is "one hundred trillion, four hundred forty-seven billion, four hundred fifty million, three hundred fifty-six thousand, one hundred thirty-one".
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