Base | Representation |
---|---|
bin | 11101010000001000011… |
… | …10000001111111110011 |
3 | 10120002022200001110022121 |
4 | 32220010032001333303 |
5 | 112431412320244243 |
6 | 2045422230015111 |
7 | 132421100452105 |
oct | 16500416017763 |
9 | 3502280043277 |
10 | 1005093134323 |
11 | 358291965113 |
12 | 1429637a7497 |
13 | 73a1a505ba5 |
14 | 3690aa2d575 |
15 | 1b2289681ed |
hex | ea04381ff3 |
1005093134323 has 2 divisors, whose sum is σ = 1005093134324. Its totient is φ = 1005093134322.
The previous prime is 1005093134321. The next prime is 1005093134351. The reversal of 1005093134323 is 3234313905001.
1005093134323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1005093134323 - 21 = 1005093134321 is a prime.
Together with 1005093134321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1005093134321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502546567161 + 502546567162.
It is an arithmetic number, because the mean of its divisors is an integer number (502546567162).
Almost surely, 21005093134323 is an apocalyptic number.
1005093134323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1005093134323 is an equidigital number, since it uses as much as digits as its factorization.
1005093134323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29160, while the sum is 34.
The spelling of 1005093134323 in words is "one trillion, five billion, ninety-three million, one hundred thirty-four thousand, three hundred twenty-three".
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