Base | Representation |
---|---|
bin | 10010101110010010… |
… | …10101100101010001 |
3 | 221221112121111211022 |
4 | 21113021111211101 |
5 | 131041303000311 |
6 | 4341241125225 |
7 | 504045406454 |
oct | 112711254521 |
9 | 27845544738 |
10 | 10052000081 |
11 | 4299101492 |
12 | 1b46489815 |
13 | c426c6056 |
14 | 6b501b49b |
15 | 3dc7305db |
hex | 257255951 |
10052000081 has 2 divisors, whose sum is σ = 10052000082. Its totient is φ = 10052000080.
The previous prime is 10052000009. The next prime is 10052000111. The reversal of 10052000081 is 18000025001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6895807681 + 3156192400 = 83041^2 + 56180^2 .
It is a cyclic number.
It is not a de Polignac number, because 10052000081 - 210 = 10051999057 is a prime.
It is a super-2 number, since 2×100520000812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10052000281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5026000040 + 5026000041.
It is an arithmetic number, because the mean of its divisors is an integer number (5026000041).
Almost surely, 210052000081 is an apocalyptic number.
It is an amenable number.
10052000081 is a deficient number, since it is larger than the sum of its proper divisors (1).
10052000081 is an equidigital number, since it uses as much as digits as its factorization.
10052000081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 10052000081 its reverse (18000025001), we get a palindrome (28052025082).
The spelling of 10052000081 in words is "ten billion, fifty-two million, eighty-one", and thus it is an aban number and an uban number.
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