10053011 has 4 divisors (see below), whose sum is σ = 10324752. Its totient is φ = 9781272.

The previous prime is 10052981. The next prime is 10053023. The reversal of 10053011 is 11035001.

10053011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11035001 = 1307 ⋅8443.

It is a cyclic number.

It is not a de Polignac number, because 10053011 - 2⁶ = 10052947 is a prime.

It is a super-2 number, since 2×10053011² = 202126060332242, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10052983 and 10053001.

It is not an unprimeable number, because it can be changed into a prime (10053031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135815 + ... + 135888.

It is an arithmetic number, because the mean of its divisors is an integer number (2581188).

Almost surely, 2^10053011 is an apocalyptic number.

10053011 is a deficient number, since it is larger than the sum of its proper divisors (271741).

10053011 is an equidigital number, since it uses as much as digits as its factorization.

10053011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 271740.

The product of its (nonzero) digits is 15, while the sum is 11.

The square root of 10053011 is about 3170.6483564091. The cubic root of 10053011 is about 215.8234940664.

Adding to 10053011 its reverse (11035001), we get a palindrome (21088012).

The spelling of 10053011 in words is "ten million, fifty-three thousand, eleven".