Base | Representation |
---|---|
bin | 11101010000100010100… |
… | …01101101001011100001 |
3 | 10120002212221021012220120 |
4 | 32220101101231023201 |
5 | 112432334410421231 |
6 | 2045500053230453 |
7 | 132426400501542 |
oct | 16502121551341 |
9 | 3502787235816 |
10 | 1005312201441 |
11 | 358394590519 |
12 | 142a05032429 |
13 | 73a53a07ac2 |
14 | 3692bb764c9 |
15 | 1b23ccdbd96 |
hex | ea1146d2e1 |
1005312201441 has 8 divisors (see below), whose sum is σ = 1360422481824. Its totient is φ = 660205027680.
The previous prime is 1005312201437. The next prime is 1005312201461. The reversal of 1005312201441 is 1441022135001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1005312201441 - 22 = 1005312201437 is a prime.
It is a super-2 number, since 2×10053122014412 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1005312201401) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2500776420 + ... + 2500776821.
It is an arithmetic number, because the mean of its divisors is an integer number (170052810228).
Almost surely, 21005312201441 is an apocalyptic number.
It is an amenable number.
1005312201441 is a deficient number, since it is larger than the sum of its proper divisors (355110280383).
1005312201441 is an equidigital number, since it uses as much as digits as its factorization.
1005312201441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5001553311.
The product of its (nonzero) digits is 960, while the sum is 24.
Adding to 1005312201441 its reverse (1441022135001), we get a palindrome (2446334336442).
The spelling of 1005312201441 in words is "one trillion, five billion, three hundred twelve million, two hundred one thousand, four hundred forty-one".
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