Base | Representation |
---|---|
bin | 10010101110011101… |
… | …10011011100111111 |
3 | 221221122022022121222 |
4 | 21113032303130333 |
5 | 131042134330101 |
6 | 4341331543555 |
7 | 504063525506 |
oct | 112716633477 |
9 | 27848268558 |
10 | 10053433151 |
11 | 42999a0143 |
12 | 1b46a5abbb |
13 | c42aa8418 |
14 | 6b52b183d |
15 | 3dc91501b |
hex | 2573b373f |
10053433151 has 8 divisors (see below), whose sum is σ = 10282947840. Its totient is φ = 9824569048.
The previous prime is 10053433139. The next prime is 10053433223. The reversal of 10053433151 is 15133435001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 10053433151 - 26 = 10053433087 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 10053433151.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10053433751) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 131321 + ... + 193266.
It is an arithmetic number, because the mean of its divisors is an integer number (1285368480).
Almost surely, 210053433151 is an apocalyptic number.
10053433151 is a deficient number, since it is larger than the sum of its proper divisors (229514689).
10053433151 is an equidigital number, since it uses as much as digits as its factorization.
10053433151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 325293.
The product of its (nonzero) digits is 2700, while the sum is 26.
Adding to 10053433151 its reverse (15133435001), we get a palindrome (25186868152).
The spelling of 10053433151 in words is "ten billion, fifty-three million, four hundred thirty-three thousand, one hundred fifty-one".
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