Base | Representation |
---|---|
bin | 101110110100001110… |
… | …0111011011111101001 |
3 | 100121111120110121002211 |
4 | 1131220130323133221 |
5 | 3121344341140433 |
6 | 114104053325121 |
7 | 10156251345505 |
oct | 1355034733751 |
9 | 317446417084 |
10 | 100536661993 |
11 | 39701363209 |
12 | 175996367a1 |
13 | 9632a5cc11 |
14 | 4c1a43b305 |
15 | 29363e58cd |
hex | 176873b7e9 |
100536661993 has 2 divisors, whose sum is σ = 100536661994. Its totient is φ = 100536661992.
The previous prime is 100536661943. The next prime is 100536662033. The reversal of 100536661993 is 399166635001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100418004544 + 118657449 = 316888^2 + 10893^2 .
It is a cyclic number.
It is not a de Polignac number, because 100536661993 - 221 = 100534564841 is a prime.
It is not a weakly prime, because it can be changed into another prime (100536661903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50268330996 + 50268330997.
It is an arithmetic number, because the mean of its divisors is an integer number (50268330997).
Almost surely, 2100536661993 is an apocalyptic number.
It is an amenable number.
100536661993 is a deficient number, since it is larger than the sum of its proper divisors (1).
100536661993 is an equidigital number, since it uses as much as digits as its factorization.
100536661993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 787320, while the sum is 49.
The spelling of 100536661993 in words is "one hundred billion, five hundred thirty-six million, six hundred sixty-one thousand, nine hundred ninety-three".
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