Base | Representation |
---|---|
bin | 1001001001001110000100… |
… | …1010111100011011001111 |
3 | 1022121011010122001012211011 |
4 | 2102103201022330123033 |
5 | 2304211043302341213 |
6 | 33214424442310051 |
7 | 2055243344164402 |
oct | 222234112743317 |
9 | 38534118035734 |
10 | 10054001215183 |
11 | 3226972640282 |
12 | 11646487b8327 |
13 | 57c11bb53aa3 |
14 | 26a88b00bd39 |
15 | 1267dabed03d |
hex | 924e12bc6cf |
10054001215183 has 2 divisors, whose sum is σ = 10054001215184. Its totient is φ = 10054001215182.
The previous prime is 10054001215157. The next prime is 10054001215229. The reversal of 10054001215183 is 38151210045001.
10054001215183 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10054001215183 - 217 = 10054001084111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10054001215483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5027000607591 + 5027000607592.
It is an arithmetic number, because the mean of its divisors is an integer number (5027000607592).
Almost surely, 210054001215183 is an apocalyptic number.
10054001215183 is a deficient number, since it is larger than the sum of its proper divisors (1).
10054001215183 is an equidigital number, since it uses as much as digits as its factorization.
10054001215183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 31.
The spelling of 10054001215183 in words is "ten trillion, fifty-four billion, one million, two hundred fifteen thousand, one hundred eighty-three".
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