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100548286382513 is a prime number
BaseRepresentation
bin10110110111001010111000…
…111001001000000110110001
3111012000022200221212121212202
4112313022320321020012301
5101134340342303220023
6553503124534432545
730115242161405204
oct2667127071100661
9435008627777782
10100548286382513
112a04631a413522
12b33ab21802755
13441487ccc9b98
141ab87c4d3793b
15b95759604128
hex5b72b8e481b1

100548286382513 has 2 divisors, whose sum is σ = 100548286382514. Its totient is φ = 100548286382512.

The previous prime is 100548286382473. The next prime is 100548286382543. The reversal of 100548286382513 is 315283682845001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 63005620761664 + 37542665620849 = 7937608^2 + 6127207^2 .

It is a cyclic number.

It is not a de Polignac number, because 100548286382513 - 216 = 100548286316977 is a prime.

It is not a weakly prime, because it can be changed into another prime (100548286382543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50274143191256 + 50274143191257.

It is an arithmetic number, because the mean of its divisors is an integer number (50274143191257).

Almost surely, 2100548286382513 is an apocalyptic number.

It is an amenable number.

100548286382513 is a deficient number, since it is larger than the sum of its proper divisors (1).

100548286382513 is an equidigital number, since it uses as much as digits as its factorization.

100548286382513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11059200, while the sum is 56.

The spelling of 100548286382513 in words is "one hundred trillion, five hundred forty-eight billion, two hundred eighty-six million, three hundred eighty-two thousand, five hundred thirteen".