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10055005056013 is a prime number
BaseRepresentation
bin1001001001010001110100…
…0000010010110000001101
31022121020201120221121120011
42102110131000102300031
52304220122243243023
633215112222153221
72055310253533141
oct222243500226015
938536646847504
1010055005056013
1132273382477a5
121164888a22811
1357c24bb07248
1426a944479221
15126848ddc50d
hex9251d012c0d

10055005056013 has 2 divisors, whose sum is σ = 10055005056014. Its totient is φ = 10055005056012.

The previous prime is 10055005055981. The next prime is 10055005056073. The reversal of 10055005056013 is 31065050055001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9603317562084 + 451687493929 = 3098922^2 + 672077^2 .

It is a cyclic number.

It is not a de Polignac number, because 10055005056013 - 25 = 10055005055981 is a prime.

It is a super-2 number, since 2×100550050560132 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10055005056073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5027502528006 + 5027502528007.

It is an arithmetic number, because the mean of its divisors is an integer number (5027502528007).

Almost surely, 210055005056013 is an apocalyptic number.

It is an amenable number.

10055005056013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10055005056013 is an equidigital number, since it uses as much as digits as its factorization.

10055005056013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11250, while the sum is 31.

The spelling of 10055005056013 in words is "ten trillion, fifty-five billion, five million, fifty-six thousand, thirteen".