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100555051105981 is a prime number
BaseRepresentation
bin10110110111010001001100…
…000110011111111010111101
3111012000222011101220011221101
4112313101030012133322331
5101134443221040342411
6553510204110133101
730115601622534103
oct2667211406377275
9435028141804841
10100555051105981
112a04918098037a
12b3402ab1b1191
1344153ba646c34
141ab8c6752bc73
15b95a034468c1
hex5b744c19febd

100555051105981 has 2 divisors, whose sum is σ = 100555051105982. Its totient is φ = 100555051105980.

The previous prime is 100555051105967. The next prime is 100555051106057. The reversal of 100555051105981 is 189501150555001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100495432117081 + 59618988900 = 10024741^2 + 244170^2 .

It is an emirp because it is prime and its reverse (189501150555001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100555051105981 - 213 = 100555051097789 is a prime.

It is a super-2 number, since 2×1005550511059812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100555051105381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50277525552990 + 50277525552991.

It is an arithmetic number, because the mean of its divisors is an integer number (50277525552991).

Almost surely, 2100555051105981 is an apocalyptic number.

It is an amenable number.

100555051105981 is a deficient number, since it is larger than the sum of its proper divisors (1).

100555051105981 is an equidigital number, since it uses as much as digits as its factorization.

100555051105981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 225000, while the sum is 46.

The spelling of 100555051105981 in words is "one hundred trillion, five hundred fifty-five billion, fifty-one million, one hundred five thousand, nine hundred eighty-one".