Base | Representation |
---|---|
bin | 10110110111010001001111… |
… | …010110011001011000001011 |
3 | 111012000222022012110000201102 |
4 | 112313101033112121120023 |
5 | 101134443324013331011 |
6 | 553510213334212015 |
7 | 30115603154010542 |
oct | 2667211726313013 |
9 | 435028265400642 |
10 | 100555105605131 |
11 | 2a0491a97143a1 |
12 | b3403054b400b |
13 | 44153c8a19158 |
14 | 1ab8c70877159 |
15 | b95a0810e73b |
hex | 5b744f59960b |
100555105605131 has 2 divisors, whose sum is σ = 100555105605132. Its totient is φ = 100555105605130.
The previous prime is 100555105605127. The next prime is 100555105605133. The reversal of 100555105605131 is 131506501555001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100555105605131 - 22 = 100555105605127 is a prime.
It is a super-2 number, since 2×1005551056051312 (a number of 29 digits) contains 22 as substring.
Together with 100555105605133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (100555105605133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50277552802565 + 50277552802566.
It is an arithmetic number, because the mean of its divisors is an integer number (50277552802566).
Almost surely, 2100555105605131 is an apocalyptic number.
100555105605131 is a deficient number, since it is larger than the sum of its proper divisors (1).
100555105605131 is an equidigital number, since it uses as much as digits as its factorization.
100555105605131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56250, while the sum is 38.
The spelling of 100555105605131 in words is "one hundred trillion, five hundred fifty-five billion, one hundred five million, six hundred five thousand, one hundred thirty-one".
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