1005551314003 has 4 divisors (see below), whose sum is σ = 1005580354680. Its totient is φ = 1005522273328.

The previous prime is 1005551313983. The next prime is 1005551314039. The reversal of 1005551314003 is 3004131555001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1005551314003 - 2⁵ = 1005551313971 is a prime.

It is a super-2 number, since 2×1005551314003² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1005551314043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14468338 + ... + 14537671.

It is an arithmetic number, because the mean of its divisors is an integer number (251395088670).

Almost surely, 2^{1005551314003} is an apocalyptic number.

1005551314003 is a deficient number, since it is larger than the sum of its proper divisors (29040677).

1005551314003 is an equidigital number, since it uses as much as digits as its factorization.

1005551314003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29040676.

The product of its (nonzero) digits is 4500, while the sum is 28.

Adding to 1005551314003 its reverse (3004131555001), we get a palindrome (4009682869004).

The spelling of 1005551314003 in words is "one trillion, five billion, five hundred fifty-one million, three hundred fourteen thousand, three".