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100555431373 is a prime number
BaseRepresentation
bin101110110100110010…
…0100001110111001101
3100121112212210011212001
41131221210201313031
53121414142300443
6114110003512301
710156600030645
oct1355144416715
9317485704761
10100555431373
1139710a129a1
12175a3988691
139636902167
144c1cb25525
152937da1d4d
hex1769921dcd

100555431373 has 2 divisors, whose sum is σ = 100555431374. Its totient is φ = 100555431372.

The previous prime is 100555431281. The next prime is 100555431437. The reversal of 100555431373 is 373134555001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91250513929 + 9304917444 = 302077^2 + 96462^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100555431373 is a prime.

It is a super-2 number, since 2×1005554313732 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100555131373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50277715686 + 50277715687.

It is an arithmetic number, because the mean of its divisors is an integer number (50277715687).

Almost surely, 2100555431373 is an apocalyptic number.

It is an amenable number.

100555431373 is a deficient number, since it is larger than the sum of its proper divisors (1).

100555431373 is an equidigital number, since it uses as much as digits as its factorization.

100555431373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 94500, while the sum is 37.

Adding to 100555431373 its reverse (373134555001), we get a palindrome (473689986374).

The spelling of 100555431373 in words is "one hundred billion, five hundred fifty-five million, four hundred thirty-one thousand, three hundred seventy-three".