Base | Representation |
---|---|
bin | 11101010010010110001… |
… | …00100100000000000001 |
3 | 10120012101111210200101222 |
4 | 32221023010210000001 |
5 | 112441331122200442 |
6 | 2050140212004425 |
7 | 132462413315222 |
oct | 16511304440001 |
9 | 3505344720358 |
10 | 1006281834497 |
11 | 358841953155 |
12 | 143035900715 |
13 | 73b79871c84 |
14 | 369c085b249 |
15 | 1b297ec08d2 |
hex | ea4b124001 |
1006281834497 has 2 divisors, whose sum is σ = 1006281834498. Its totient is φ = 1006281834496.
The previous prime is 1006281834449. The next prime is 1006281834517. The reversal of 1006281834497 is 7944381826001.
It is a Cunningham number, because it is equal to 10031362+1.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1006281834496 + 1 = 1003136^2 + 1^2 .
It is a cyclic number.
It is not a de Polignac number, because 1006281834497 - 26 = 1006281834433 is a prime.
It is not a weakly prime, because it can be changed into another prime (1006281834427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 503140917248 + 503140917249.
It is an arithmetic number, because the mean of its divisors is an integer number (503140917249).
Almost surely, 21006281834497 is an apocalyptic number.
It is an amenable number.
1006281834497 is a deficient number, since it is larger than the sum of its proper divisors (1).
1006281834497 is an equidigital number, since it uses as much as digits as its factorization.
1006281834497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2322432, while the sum is 53.
The spelling of 1006281834497 in words is "one trillion, six billion, two hundred eighty-one million, eight hundred thirty-four thousand, four hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •