Base | Representation |
---|---|
bin | 1001001001110011010100… |
… | …0111011000001110100001 |
3 | 1022122002221102120202211022 |
4 | 2102130311013120032201 |
5 | 2304342032333014332 |
6 | 33223200524255225 |
7 | 2056046201210354 |
oct | 222346507301641 |
9 | 38562842522738 |
10 | 10063999501217 |
11 | 3230133394592 |
12 | 11665790a1515 |
13 | 58005339107c |
14 | 26b158c4629b |
15 | 126bc386d212 |
hex | 927351d83a1 |
10063999501217 has 2 divisors, whose sum is σ = 10063999501218. Its totient is φ = 10063999501216.
The previous prime is 10063999501183. The next prime is 10063999501253. The reversal of 10063999501217 is 71210599936001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6864483840256 + 3199515660961 = 2620016^2 + 1788719^2 .
It is a cyclic number.
It is not a de Polignac number, because 10063999501217 - 210 = 10063999500193 is a prime.
It is not a weakly prime, because it can be changed into another prime (10063999507217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5031999750608 + 5031999750609.
It is an arithmetic number, because the mean of its divisors is an integer number (5031999750609).
Almost surely, 210063999501217 is an apocalyptic number.
It is an amenable number.
10063999501217 is a deficient number, since it is larger than the sum of its proper divisors (1).
10063999501217 is an equidigital number, since it uses as much as digits as its factorization.
10063999501217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 918540, while the sum is 53.
The spelling of 10063999501217 in words is "ten trillion, sixty-three billion, nine hundred ninety-nine million, five hundred one thousand, two hundred seventeen".
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