10063999501253 has 2 divisors, whose sum is σ = 10063999501254. Its totient is φ = 10063999501252.

The previous prime is 10063999501217. The next prime is 10063999501273. The reversal of 10063999501253 is 35210599936001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9702271833409 + 361727667844 = 3114847^2 + 601438^2 .

It is a cyclic number.

It is not a de Polignac number, because 10063999501253 - 2¹⁰ = 10063999500229 is a prime.

It is a super-2 number, since 2×10063999501253² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10063999501195 and 10063999501204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10063999501273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5031999750626 + 5031999750627.

It is an arithmetic number, because the mean of its divisors is an integer number (5031999750627).

Almost surely, 2^{10063999501253} is an apocalyptic number.

It is an amenable number.

10063999501253 is a deficient number, since it is larger than the sum of its proper divisors (1).

10063999501253 is an equidigital number, since it uses as much as digits as its factorization.

10063999501253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1968300, while the sum is 53.

The spelling of 10063999501253 in words is "ten trillion, sixty-three billion, nine hundred ninety-nine million, five hundred one thousand, two hundred fifty-three".