10084100878453 has 4 divisors (see below), whose sum is σ = 11524686718240. Its totient is φ = 8643515038668.

The previous prime is 10084100878447. The next prime is 10084100878459. The reversal of 10084100878453 is 35487800148001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (10084100878447) and next prime (10084100878459).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10084100878453 is a prime.

It is a super-3 number, since 3×10084100878453³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10084100878397 and 10084100878406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10084100878459) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 720292919883 + ... + 720292919896.

It is an arithmetic number, because the mean of its divisors is an integer number (2881171679560).

Almost surely, 2^{10084100878453} is an apocalyptic number.

It is an amenable number.

10084100878453 is a deficient number, since it is larger than the sum of its proper divisors (1440585839787).

10084100878453 is an equidigital number, since it uses as much as digits as its factorization.

10084100878453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1440585839786.

The product of its (nonzero) digits is 860160, while the sum is 49.

The spelling of 10084100878453 in words is "ten trillion, eighty-four billion, one hundred million, eight hundred seventy-eight thousand, four hundred fifty-three".